Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

A sample of neon gas has a volume of 752 ML 25.0 C what will the volume of 100.0's see if the pressure is constant

Sagot :

The Formula is: [tex] \frac{V1}{T1} = \frac{V2}{T2} [/tex]

We know that V1 = 752 ML
T1 = 25 + 273 = 289
T2 = 100 + 273 = 373
V2 = ? 
So, we need to find V2, using the formula mentioned, so you replace each term by it's value, and Let x be the value of V2, so you get:
[tex] \frac{752}{289} = \frac{x}{373} [/tex]

Then, you move 373 (T2) next to other term, and since it's a division, it become a multiplication. so you get:
[tex] \frac{752}{289} * 373 = x[/tex]

You do the calculations, and you get about x = 941

So, V2 = 941

So the volume at 100.0's is 941

Hope this Helps! :)