key4seth23
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how do you soLve this problem using Who:
4(1+3X)+4X=-18+5X

Sagot :

SoapyMcTavish
[tex]4(1+3x)+4x= -18+5x[/tex]

First, you develop, so you get:
[tex]4+12x+4x = -18+5x[/tex]

Then, you put known numbers (numbers without x) apart, and unknown numbers (numbers with x) apart. And remember, moving from a side to another change the sign of the Number (Positive become negative, and negative become positive) so you get:
[tex]12x+4x-5x = -18-4[/tex]

Now, you do the calculations, you get:
[tex]11x = -22[/tex]

Then, you move 11 to the other side. And since it was in a multiplication equation, it become a division. So you get:
[tex]x = - \frac{22}{11} [/tex]
[tex]x = -2[/tex]

Hope this Helps! :D

Panoyin
    4(1 + 3x) + 4x = -18 + 5x
4(1) + 4(3x) + 4x = -18 + 5x
      4 + 12x + 4x = -18 + 5x
              4 + 16x = -18 + 5x
                    - 5x           - 5x
              4 + 11x = -18
            - 4               - 4
                    11x = -22
                     11      11
                        x = -2
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