At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Question: Simplify [tex]\frac{\sqrt{8x^2}}{\sqrt{2x}}[/tex].
First off, you never want square roots on the bottom of a fraction, so let's multiply both sides by [tex]\sqrt{2x}[/tex] to get rid of it. All we have to do from there is simplify!
[tex]\frac{\sqrt{8x^2}}{\sqrt{2x}}*\frac{\sqrt{2x}}{\sqrt{2x}}=\frac{\sqrt{8x^2}*\sqrt{2x}}{2x}}=\frac{\sqrt{16x^3}}{2x}=\frac{4x\sqrt{x}}{2x}=\boxed{2\sqrt{x}}[/tex]
First off, you never want square roots on the bottom of a fraction, so let's multiply both sides by [tex]\sqrt{2x}[/tex] to get rid of it. All we have to do from there is simplify!
[tex]\frac{\sqrt{8x^2}}{\sqrt{2x}}*\frac{\sqrt{2x}}{\sqrt{2x}}=\frac{\sqrt{8x^2}*\sqrt{2x}}{2x}}=\frac{\sqrt{16x^3}}{2x}=\frac{4x\sqrt{x}}{2x}=\boxed{2\sqrt{x}}[/tex]
[tex] \sqrt{\frac{8x^{2}}{2x}} = \frac{\sqrt{8x^{2}}}{\sqrt{2x}} = \frac{\sqrt{4}\sqrt{x^{2}}\sqrt{2}}{\sqrt{2x}} = \frac{2x\sqrt{2}}{\sqrt{2x}} = \frac{2x}{\sqrt{x}} = 2\sqrt{x} [/tex]
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.