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Sagot :
[tex] {\sqrt{\frac{72x^{3}}{50x^{{2}}}} = \frac{\sqrt{72x^{3}}}{\sqrt{50x^{2}}} = \frac {\sqrt{36 * x^{2} * 2 * x}}{\sqrt{25 * x^{2} * 2}} = \frac{\sqrt{36}\sqrt{x^{2}}\sqrt{2}\sqrt{x}}{\sqrt{25}\sqrt{x^{2}}\sqrt{2}} = \frac{6x\sqrt{2x}}{5x\sqrt{2}} = 1\frac{1}{5}\sqrt{x} [/tex]
The answer is equal to C. [tex] \frac{6\sqrt{x}}{5} [/tex].
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