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The sum of 1/3 and twice a number is equal to 2/3 subtracted from three the number.find the number

Sagot :

the number = y

2y + 1/3 = 2/3 - 3y
(add 3y to both sides)
5y + 1/3 = 2/3
(subtract 1/3 from both sides to isolate y)
5y = 1/3
(divide by 5)
y = 1/15
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