kaylahonea36201
Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

2log base of 4 x+ log base of 4 (x-1)=1

Sagot :

AL2006

First, let's review a couple of basics:

2 x log (something) is the same as log(something²)

The sum of the logs of 2 numbers is the same as the log of their product. 

==========================================

So    2 log₄(x) = log₄(x²)

From the given equation:        log₄(x²) + log₄(x-1)  =  1

Sum of logs = log of the product:  log₄( [x] [x-1] ) = 1

Raise 4 to the power of each side:         (x) (x-1) = 4

Eliminate parentheses on the left:             x² - x = 4

Subtract  4  from each side:                x² - x - 4 = 0

Mash this through the quadratic formula, and you have

   x = 0.5 + 0.5√17  =   2.562  (rounded)

   x = 0.5 - 0.5√17  =  -1.562  (rounded)


We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.