kaylahonea36201
Answered

Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

2log base of 4 x+ log base of 4 (x-1)=1

Sagot :

AL2006

First, let's review a couple of basics:

2 x log (something) is the same as log(something²)

The sum of the logs of 2 numbers is the same as the log of their product. 

==========================================

So    2 log₄(x) = log₄(x²)

From the given equation:        log₄(x²) + log₄(x-1)  =  1

Sum of logs = log of the product:  log₄( [x] [x-1] ) = 1

Raise 4 to the power of each side:         (x) (x-1) = 4

Eliminate parentheses on the left:             x² - x = 4

Subtract  4  from each side:                x² - x - 4 = 0

Mash this through the quadratic formula, and you have

   x = 0.5 + 0.5√17  =   2.562  (rounded)

   x = 0.5 - 0.5√17  =  -1.562  (rounded)


Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.