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solve algebraically: the soccer field has an area of 6000 square yards. The field is 40 yards longer than its width. What are the dimensions of the field in years

Sagot :

belcatya
lets width od field is x , x>0 (if x<0 it is no sense) yards and length is (x+40)yards
So square of field is x(x+40)=6000
x²+40x=6000
x²+40x-6000=0
(x+100)(x-60)=0
x₁=-100 no sense
x₂=60 yards - width of field
x+40=x+60=100 yards - length of field
Answer: 60 yards - width of field, 100 yards - length of field
 
A= l x w
x= width
x + 40 = length

6000= x (x+40)
       0= x^2 + 40x-6000)
       0= ( x+100)  (x-60)
    0nly need the positive root, lengths are not negative
  x-60=0
       x= 60 yds  width
60+40= 100 yds. length

Hope this helps

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