math97
Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

solve algebraically: the soccer field has an area of 6000 square yards. The field is 40 yards longer than its width. What are the dimensions of the field in years

Sagot :

belcatya
lets width od field is x , x>0 (if x<0 it is no sense) yards and length is (x+40)yards
So square of field is x(x+40)=6000
x²+40x=6000
x²+40x-6000=0
(x+100)(x-60)=0
x₁=-100 no sense
x₂=60 yards - width of field
x+40=x+60=100 yards - length of field
Answer: 60 yards - width of field, 100 yards - length of field
 
A= l x w
x= width
x + 40 = length

6000= x (x+40)
       0= x^2 + 40x-6000)
       0= ( x+100)  (x-60)
    0nly need the positive root, lengths are not negative
  x-60=0
       x= 60 yds  width
60+40= 100 yds. length

Hope this helps

We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.