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Write the equation of the circle that has a diameter with endpoints (6,-1) and (0,-7).

Sagot :

[tex]d = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2}} [/tex]
[tex]d = \sqrt{(0 - (-1))^{2} + (-7 - (-1))^{2}} [/tex]
[tex]d = \sqrt{(0 + 1)^{2} + (-7 + 1)^{2}} [/tex]
[tex]d = \sqrt{(1)^{2} + (-6)^{2}} [/tex]
[tex]d = \sqrt{1 + 36} [/tex]
[tex]d = \sqrt{37} [/tex]
[tex]d = 6.083[/tex]