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4x-2y=7
-3x+3y=10
Find the point of intersection of the equations

Sagot :

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4x-2y=7 (1)
-3x+3y=10 (2)
3y= 3x+10
y= x+10/3 (3)
sub (3) into (1)
4x-2(x+10/3)=7
4x-2x-20/3=7
2x-20/3=7
    +20/3  +20/3
2x= 41/3
x= (41/3) / 2
x= 41/6
sub x= 41/6 into (3)
y= 41/6+10/3
= 61/6

Therefore the point of intersection is (41/6, 61/6) 
Panoyin
  4x - 2y = 7   ⇒ -12x +   6y = -21
-3x + 3y = 10 ⇒ -12x + 12y = 40
                                       -6y = -61
                                        -6      -6
                                           y = 10¹/₆
                          4x - 2(10¹/₆) = 7
                                4x - 8¹/₃ = 7
                                    + 8¹/₃ + 8¹/₃
                                         4x = 15¹/₃
                                          4        4
                                           x = 3⁵/₆
                                     (x, y) = (3⁵/₆, 10¹/₆)
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