JessicaRufus
Answered

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Simplify the expression: 1/1+cot^2x

Sagot :

belcatya
[tex] \frac{1}{1+ ctg^{2}x } [/tex]=[tex] \frac{1}{1+ \frac{cos ^{2} x}{sin ^{2}x} } = \frac{1}{ \frac{sin ^{2}x+cos ^{2} x }{ sin^{2} x} }= \frac{sin ^{2} x}{sin ^{2}x+cos ^{2} x } =sin ^{2}x [/tex]
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Answer:C. Sin^2x

Step-by-step explanation:

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