Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
if you noted 2-6+4=0 ⇒z₁=1 ⇒ one of factor is (z-1)
so 2z²-2z-4z+4=0
(2z²-2z)-(4z-4)=0
2z(z-1)-4(z-1)=0
(z-1)(2z-4)=0
2z-4=0
2z=4
z₂=2
Answer: z₁=1, z₂=2
so 2z²-2z-4z+4=0
(2z²-2z)-(4z-4)=0
2z(z-1)-4(z-1)=0
(z-1)(2z-4)=0
2z-4=0
2z=4
z₂=2
Answer: z₁=1, z₂=2
2z²-6z+4=0
Divide by 2 to everything
z²-3z+2=0
Think of two numbers that multiply to get 2 and add to get -3 in order to factorise
These numbers are -2 and -1
(z-2)(z-1)=0
Therefore z= 2 and z= 1
Divide by 2 to everything
z²-3z+2=0
Think of two numbers that multiply to get 2 and add to get -3 in order to factorise
These numbers are -2 and -1
(z-2)(z-1)=0
Therefore z= 2 and z= 1
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.