Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
if you noted 2-6+4=0 ⇒z₁=1 ⇒ one of factor is (z-1)
so 2z²-2z-4z+4=0
(2z²-2z)-(4z-4)=0
2z(z-1)-4(z-1)=0
(z-1)(2z-4)=0
2z-4=0
2z=4
z₂=2
Answer: z₁=1, z₂=2
so 2z²-2z-4z+4=0
(2z²-2z)-(4z-4)=0
2z(z-1)-4(z-1)=0
(z-1)(2z-4)=0
2z-4=0
2z=4
z₂=2
Answer: z₁=1, z₂=2
2z²-6z+4=0
Divide by 2 to everything
z²-3z+2=0
Think of two numbers that multiply to get 2 and add to get -3 in order to factorise
These numbers are -2 and -1
(z-2)(z-1)=0
Therefore z= 2 and z= 1
Divide by 2 to everything
z²-3z+2=0
Think of two numbers that multiply to get 2 and add to get -3 in order to factorise
These numbers are -2 and -1
(z-2)(z-1)=0
Therefore z= 2 and z= 1
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.