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2x+3y=10 and 4x+6y=12 in slope intercept form

Sagot :

TSO
Slope intercept form is y=mx+b

So:

2x + 3y = 10

Subtract 2x on both sides

3y = -2x + 10

Divide 3 on both sides

y = -2/3x + 10/3

Next equation:

4x + 6y = 12

Subtract 4x on both sides

6y = -4x + 12

Divide by 6 on both sides

y = -2/3 x + 2
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