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Sagot :
Acceleration measures how fast the speed changes over time.
So, over 10s, the aircraft's speed changes by 3[tex] \frac{m}{ s^{2} } [/tex] * 10s
So, the change is 30[tex] \frac{m}{s} [/tex]
Note that the one of the second units cancels out in the answer.
So, over 10s, the aircraft's speed changes by 3[tex] \frac{m}{ s^{2} } [/tex] * 10s
So, the change is 30[tex] \frac{m}{s} [/tex]
Note that the one of the second units cancels out in the answer.
To solve this, let's use the formula a=(v''-v')÷(t)
3=(v''-0)÷(10)
3=v÷10
Now isolate for velocity
v"=(3)(10)
v"=30 m/s!
3=(v''-0)÷(10)
3=v÷10
Now isolate for velocity
v"=(3)(10)
v"=30 m/s!
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