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a vertical pole 10 ft. tall casts a 14-foot shadow. what is the angle of elevation of the sun to the nearest degree?

Sagot :

RedRicin
Draw a right triangle.

[tex]tan(theta) = \frac{opposite}{adjacent}[/tex]

[tex]tan(theta) = \frac{10}{14}[/tex]

Arctangent (tan^-1) can be used to find theta.

[tex]tan^{-1}(\frac{10}{14})=theta[/tex]

[tex]theta\ is\ approx\ \boxed{36\ degrees}[/tex]
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