Picknell14
Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

What is the derivative of y=ln(sec(x)+tan(x))y=ln(sec(x)+tan(x))?

Sagot :

kittymaniac
The derivative of ln(u) is 1/u * the derivative of u.

[tex]y = ln(sec(x)+tan(x)) \\ \\ y' = \frac{1}{sec(x)+tan(x)} * [tan(x)sec(x) + sec^2(x)] \\ \\ y' = \frac{sec(x)(sec(x) + tan(x))}{sec(x)+tan(x)} \\ \\ y' = sec(x) + C[/tex]

I hope this helps! :)
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.