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Sagot :
To answer this question, we need to find the force acting on the two objects.
f=ma
f=(6)(2)
f=12 newtons
So, now we can determine the acceleration of the second object using the same formula!
f=ma
12=(4)a
3=a
So the acceleration of the smaller object is 3 meters per second squared!
f=ma
f=(6)(2)
f=12 newtons
So, now we can determine the acceleration of the second object using the same formula!
f=ma
12=(4)a
3=a
So the acceleration of the smaller object is 3 meters per second squared!
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