Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
To answer this question, we need to find the force acting on the two objects.
f=ma
f=(6)(2)
f=12 newtons
So, now we can determine the acceleration of the second object using the same formula!
f=ma
12=(4)a
3=a
So the acceleration of the smaller object is 3 meters per second squared!
f=ma
f=(6)(2)
f=12 newtons
So, now we can determine the acceleration of the second object using the same formula!
f=ma
12=(4)a
3=a
So the acceleration of the smaller object is 3 meters per second squared!
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.
