Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
To answer this question, we need to find the force acting on the two objects.
f=ma
f=(6)(2)
f=12 newtons
So, now we can determine the acceleration of the second object using the same formula!
f=ma
12=(4)a
3=a
So the acceleration of the smaller object is 3 meters per second squared!
f=ma
f=(6)(2)
f=12 newtons
So, now we can determine the acceleration of the second object using the same formula!
f=ma
12=(4)a
3=a
So the acceleration of the smaller object is 3 meters per second squared!
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
