Answered

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2log4-log3+2logx-4=0

Sagot :

TheGreatDerp
2log4-log3+2logx-4=0
I assume it's find x
2log4=log4^2=log16
2logx=logx^2
-log3=log3^(-1)=log1/3
log(16x^2)/3=4
base is unknown, so if it's different just plug it in for the lower values of 10
we'll just assume it's common log's base is 10
10^4=(16x^2)/3
30000=16x^2
x^2=30000/16
x=(30000^1/2)/4 which is about 43.301
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