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Sagot :
CuCl2 is Dichloride Copper, or Copper II Chloride.
In this Molecule, there is 1 atom of Copper for every 2 atoms of Chlorine.
If you go to the periodic table, you'll see that copper has a mass of 63.5 amu, and the chlorine 35.45 amu.
Which mean that the mass of CuCl2 is 63.5 + 35.45*2 = 63.5 + 70.9 = 134.4 g/mol.
Then, you find the ration of the mass of each atom and multiply by 100.
Ratio of Copper: [tex] \frac{63.5}{134.4} * 100[/tex] and you get about 47.2%
Ration of chlorice (Cl2): [tex] \frac{70.9}{134.4} * 100[/tex] and you get about 52.8%.
So, the percent composition of CuCl2 is 47.2% of Copper and 52.8% of chlorine.
Hope this Helps :)
In this Molecule, there is 1 atom of Copper for every 2 atoms of Chlorine.
If you go to the periodic table, you'll see that copper has a mass of 63.5 amu, and the chlorine 35.45 amu.
Which mean that the mass of CuCl2 is 63.5 + 35.45*2 = 63.5 + 70.9 = 134.4 g/mol.
Then, you find the ration of the mass of each atom and multiply by 100.
Ratio of Copper: [tex] \frac{63.5}{134.4} * 100[/tex] and you get about 47.2%
Ration of chlorice (Cl2): [tex] \frac{70.9}{134.4} * 100[/tex] and you get about 52.8%.
So, the percent composition of CuCl2 is 47.2% of Copper and 52.8% of chlorine.
Hope this Helps :)
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