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what is the mean absolute deviation of 26 43 48 29 16 30

Sagot :

The mean absolute deviation of a number set is the average distance between each value and the mean. This is obtained by finding the mean of the set, determining the absolute value difference between each number, and the mean and calculating the average of these differences.
The mean of the set is ( 26 + 43 + 48 + 29 + 16 + 30 ) / 6 = 32 ;
 the absolute value difference between each number:
/ 26 - 32 / = 6 ; / 43 - 32 / = 11 ; / 48 - 32 / = 16 ; / 29 - 32 / = 3 ; / 16 - 32 / = 16 ;
 / 30 - 32 / = 2 ;

the mean absolute deviation of 26 43 48 29 16 30 is ( 6 + 11 + 16 + 3 + 16 + 2 ) / 6 = 9 ;