Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Calculate the density:
[tex]m=8.97 \ g \\ V=0.79 \ cm^3 \\ \\ \rho=\frac{m}{V}=\frac{8.79 \ g}{0.79 \ cm^3} \approx 11.35 \ \frac{g}{cm^3}[/tex]
It's the density of lead, so the answer is C.
[tex]m=8.97 \ g \\ V=0.79 \ cm^3 \\ \\ \rho=\frac{m}{V}=\frac{8.79 \ g}{0.79 \ cm^3} \approx 11.35 \ \frac{g}{cm^3}[/tex]
It's the density of lead, so the answer is C.
Answer: The correct option is Option C.
Explanation:
To identify the sample, we will determine the density of the unknown sample and match it with the specific densities. The equation used to calculate the density of a sample is given by:
[tex]Density=\frac{Mass}{Volume}[/tex]
We are given:
Mass of the sample = 8.97 g
Volume of the sample = [tex]0.79cm^3[/tex]
Putting values in above equation, we get:
[tex]\text{Density of the sample}=\frac{8.97g}{0.79cm^3}=11.35g/cm^3[/tex]
This value of density matches the specific density of lead.
Hence, the correct option is Option C.
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.