Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
[tex]2 \sqrt{6} + 3 \sqrt{96} [/tex]
First break down 96 into the smaller factors of 6 and 16
[tex]2 \sqrt{6} + 3 \sqrt{16*6} [/tex]
Now the square root of 16 comes out even as 4 so you can evaluate that part.
[tex]2 \sqrt{6} + (3 * 4) \sqrt{6} [/tex]
Multiply 3 and 4 to get 12
[tex]2 \sqrt{6} + 12 \sqrt{6} [/tex]
And now that the square roots on both parts of the eqations are the same you can add them to get: [tex]14 \sqrt{6} [/tex]
Therefore your answer is a
First break down 96 into the smaller factors of 6 and 16
[tex]2 \sqrt{6} + 3 \sqrt{16*6} [/tex]
Now the square root of 16 comes out even as 4 so you can evaluate that part.
[tex]2 \sqrt{6} + (3 * 4) \sqrt{6} [/tex]
Multiply 3 and 4 to get 12
[tex]2 \sqrt{6} + 12 \sqrt{6} [/tex]
And now that the square roots on both parts of the eqations are the same you can add them to get: [tex]14 \sqrt{6} [/tex]
Therefore your answer is a
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.
