Answered

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2loge3 + loge x - loge2 = loge3

Solve for x

Sagot :

konrad509
[tex]2\ln 3+\ln x-\ln 2=\ln 3\\ \ln x=-\ln 3+\ln 2\\ \ln x=\ln \dfrac{1}{3}+\ln 2\\ \ln x=\ln \dfrac{2}{3}\\ x=\dfrac{2}{3}[/tex]
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