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## Sagot :

I spent a long time drawing and labeling a diagram as well as writing out a detailed formulaic explanation.

The** required Area **of the** parallelogram** is **43.868units.**

Given that,

**ABCD ** is a **parallelogram,**

**AC **= **9cm**, **DC** =** 11cm** and **DAC** =** 100degree**

We have to **find,**

The **area** of a **parallelogram**.

**According** to the** question,**

By the **law** of **sin angle,**

[tex]\frac{SinA}{a} = \frac{SinD}{d} \\\frac{Sin100}{11} = \frac{SinD}{9} \\\frac{SinD}{9} = 0.0895\\SinD = 53.69[/tex]

**D** = **53.69**

In the** triangle sum **of all **angles **in** 180degree.**

∠A + ∠ACD + ∠D = 180

100 + ∠ACD + 53.69 = 180

∠ACD + 153.69 = 180

∠ACD = 180-153.69

**∠ACD **=** 26.31**

The** base** which is** 11.** for **height **make** right triangle** and **angle ACQ **is** right angle**.

[tex]SinACQ = \frac{h}{AC} \\SinACQ = \frac{h}{9} \\sin26.31 = \frac{h}{9} \\0.443 = \frac{h}{9} \\h = 3.98[/tex]

**Area** of the** parallelogram** = Base × Height

**Area** of the **parallelogram **= (11)(3.98)

**Area** of the** parallelogram **= 43.868

Hence, The** required Area **of the** parallelogram** is **43.868units.**

For more information about** Parallelogram **click the link given below.

https://brainly.com/question/9680084