Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To apply the quadratic formula, the right side must be equal to 0.
[tex]2w^2-28w=-98 \\ 2w^2-28w+98=0[/tex]
Now you can apply the quadratic formula [tex]\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex] to find the solution for w.
[tex]\frac{-(-28)\±\sqrt{(-28)^2-4(2)(98)}}{2(2)} = \frac{28\±\sqrt{784-784}}{4} = \frac{28}4 = \boxed{7} [/tex]
(The quadratic formula is highly unnecessary in this problem, however. You could easily divide all values by 2 to get w²-14w+49=0, which factors into (w-7)²=0, for which 7 is the only solution which puts a factor of the quadratic equal to 0.)
[tex]2w^2-28w=-98 \\ 2w^2-28w+98=0[/tex]
Now you can apply the quadratic formula [tex]\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex] to find the solution for w.
[tex]\frac{-(-28)\±\sqrt{(-28)^2-4(2)(98)}}{2(2)} = \frac{28\±\sqrt{784-784}}{4} = \frac{28}4 = \boxed{7} [/tex]
(The quadratic formula is highly unnecessary in this problem, however. You could easily divide all values by 2 to get w²-14w+49=0, which factors into (w-7)²=0, for which 7 is the only solution which puts a factor of the quadratic equal to 0.)
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.