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There are 4 red balls, 6 white balls, and 3 blue balls in a bag. If one ball is drawn from the bag at random, what is the probability that it is not white?

Sagot :

jclainwizard
7/13 13 balls total minus 6 for the white balls 7 /13 are not white

JeanaShupp

Answer: [tex]\dfrac{7}{13}[/tex]

Step-by-step explanation:

Given: The total number of balls = [tex]4+6+3=13[/tex]

The number of white balls = 6

The balls which are not white =  [tex]13-6=7[/tex]

If one ball is drawn from the bag at random, the probability that it is not white is given by :-

[tex]\text{P(balls not white)}=\dfrac{\text{balls not white}}{\text{Total balls}}=\dfrac{7}{13}[/tex]

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