Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

There are 4 red balls, 6 white balls, and 3 blue balls in a bag. If one ball is drawn from the bag at random, what is the probability that it is not white?

Sagot :

jclainwizard
7/13 13 balls total minus 6 for the white balls 7 /13 are not white

JeanaShupp

Answer: [tex]\dfrac{7}{13}[/tex]

Step-by-step explanation:

Given: The total number of balls = [tex]4+6+3=13[/tex]

The number of white balls = 6

The balls which are not white =  [tex]13-6=7[/tex]

If one ball is drawn from the bag at random, the probability that it is not white is given by :-

[tex]\text{P(balls not white)}=\dfrac{\text{balls not white}}{\text{Total balls}}=\dfrac{7}{13}[/tex]

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.