Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
X^2+6x=7
Half the middle term which 6. And square the result
6/2 =3
3^2 =9
This 9 will be added in the left side after the 6x. And also to be added at the right side. Because there is a rule that what you did in left side is you need to to in the right side to be equal.
X^2+6x + 9 = 7 + 9
Convert the left side equation into squared and the other side add the two numbers
(X+3)^2 = 16
Squared both sides to remove tye 2
X+3 = + and - 4
You need to right two signs
so if in ax^2+bx+c form then
for the completing the square
(b/2)^2=c so
if b=6 then
b/2=6/2=3
(b/2)^2=(6/2)^2=(3)^2=9
so c=9
x^2+6x=7
add 9 to both sides
x^2+6x+9=16
so factor and get
(x+3)^2=16
for fun solve
16=4^2
(x+3)^2=4^2 or -4
square root both sides
x+3=4 or -4
solve 2 equaitons
1. x+3=4
sutract 3 from both sides
x=-1
2. x+3=-4
subtract 3 from both sides
x=-7
x=-1 or -7
solution set=S={x|x=-1,-7}
answer is x^2+6x+9=16
for the completing the square
(b/2)^2=c so
if b=6 then
b/2=6/2=3
(b/2)^2=(6/2)^2=(3)^2=9
so c=9
x^2+6x=7
add 9 to both sides
x^2+6x+9=16
so factor and get
(x+3)^2=16
for fun solve
16=4^2
(x+3)^2=4^2 or -4
square root both sides
x+3=4 or -4
solve 2 equaitons
1. x+3=4
sutract 3 from both sides
x=-1
2. x+3=-4
subtract 3 from both sides
x=-7
x=-1 or -7
solution set=S={x|x=-1,-7}
answer is x^2+6x+9=16
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.