Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
im assuming that you mean 4/(x+1)-2/(x+2)
first get a common denominator of (x+1)(x+2)
multiply 4/(x+1) times (x+2)/(x+2) and get (4x+8)/[(x+1)(x+2)]
then multiply -2/(x+2) times (x+1)/(x+1) and get (-2x-2)/[(x+1)(x+2)]
next connect like parts
(4x+8-2x-2)/[(x+1)(x+2)]
the answer is (2x+6)/[(x+1)(x+2)]
first get a common denominator of (x+1)(x+2)
multiply 4/(x+1) times (x+2)/(x+2) and get (4x+8)/[(x+1)(x+2)]
then multiply -2/(x+2) times (x+1)/(x+1) and get (-2x-2)/[(x+1)(x+2)]
next connect like parts
(4x+8-2x-2)/[(x+1)(x+2)]
the answer is (2x+6)/[(x+1)(x+2)]
[tex]\frac{4}{x + 1} - \frac{2}{x + 2} = \frac{4(x + 2)}{(x + 1)(x + 2)} - \frac{2(x + 1)}{(x + 1)(x + 2)} = \frac{4x + 8}{x^{2} + 3x + 2} - \frac{2x + 2}{x^{2} + 3x + 2} = \frac{2x + 6}{x^{2} + 3x + 2} [/tex]
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.