15Twilight
Answered

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If sin Θ = -square root3/2 and π < Θ < 3pi/2 , what are the values of cos Θ and tan Θ

Sagot :

belcatya

π < θ < 3pi/2, so θ ∈ 3 quadrant,
so cosθ<0, tg θ>0

we know that sin²θ+cos²θ=1

cosθ=-√(1-sin²θ)=-√1-[tex] (\frac{ \sqrt{3} }{2}) [/tex]²=-√(1-[tex] \frac{3}{4}) [/tex]=- √0.25=- 0.5
tgθ=[tex] \frac{sin \alpha }{cos \alpha } [/tex]=  - [tex] \frac{ \sqrt{3} }{2}: (- 0.5)[/tex]=√3


P.s. θ=[tex] \alpha [/tex], i can't put θ in formula, sorry










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