Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
[tex]y = x^{2} + 3x - 4[/tex]
[tex]x^{2} + 3x - 4 = 0[/tex]
[tex]x = \frac{-(3) +/- \sqrt{(3)^{2} - 4(1)(-4)}}{2(1)} [/tex]
[tex]x = \frac{-3 +/- \sqrt{9 + 16}}{2} [/tex]
[tex]x = \frac{-3 +/- \sqrt{25}}{2} [/tex]
[tex]x = \frac{-3 +/- 5}{2} [/tex]
[tex]x = \frac{3 + 5}{2} [/tex] [tex]x = \frac{3 - 5}{2} [/tex]
[tex]x = \frac{8}{2} [/tex] [tex]x = \frac{-2}{2} [/tex]
[tex]x = 4[/tex] [tex]x = -1[/tex]
[tex]y = x^{2} + 3x - 4[/tex]
[tex]y = (4)^{2} + 3(4) - 4[/tex]
[tex]y = 16 + 12 - 4[/tex]
[tex]y = 28 - 4[/tex]
[tex]y = 24[/tex]
[tex](x, y) = (4, 24)[/tex]
or
[tex]y = x^{2} + 3x - 4[/tex]
[tex]y = (-1)^{2} + 3(-1) - 4[/tex]
[tex]y = 1 - 3 - 4[/tex]
[tex]y = -2 - 4[/tex]
[tex]y = -6[/tex]
[tex](x, y) = (-1, -6)[/tex]
[tex]x^{2} + 3x - 4 = 0[/tex]
[tex]x = \frac{-(3) +/- \sqrt{(3)^{2} - 4(1)(-4)}}{2(1)} [/tex]
[tex]x = \frac{-3 +/- \sqrt{9 + 16}}{2} [/tex]
[tex]x = \frac{-3 +/- \sqrt{25}}{2} [/tex]
[tex]x = \frac{-3 +/- 5}{2} [/tex]
[tex]x = \frac{3 + 5}{2} [/tex] [tex]x = \frac{3 - 5}{2} [/tex]
[tex]x = \frac{8}{2} [/tex] [tex]x = \frac{-2}{2} [/tex]
[tex]x = 4[/tex] [tex]x = -1[/tex]
[tex]y = x^{2} + 3x - 4[/tex]
[tex]y = (4)^{2} + 3(4) - 4[/tex]
[tex]y = 16 + 12 - 4[/tex]
[tex]y = 28 - 4[/tex]
[tex]y = 24[/tex]
[tex](x, y) = (4, 24)[/tex]
or
[tex]y = x^{2} + 3x - 4[/tex]
[tex]y = (-1)^{2} + 3(-1) - 4[/tex]
[tex]y = 1 - 3 - 4[/tex]
[tex]y = -2 - 4[/tex]
[tex]y = -6[/tex]
[tex](x, y) = (-1, -6)[/tex]
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.