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A rectangular poster has an area of 190 inches squared. The height of the poster is one inch less than twice its width. Find the dimension of the poster.
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Sagot :

Set the height to h, and the width to w.

We know that wh=190 and h=2w-1.

Substituting 2w-1 for h, we have:

w(2w-1)=190

So:
2w^2-w-190=0

Factoring this equation, we get (2w+19)(w-10)=0.  The solutions to this equation are -9.5 and 10, but clearly the width must be positive, Substituting 10 for the width, we get 10*2-1=19 for the height.
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