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how do you solve \r+3=r-3 by the way / is a radical sign

Sagot :

Subtract three from both sides to get:

[tex] \sqrt{r} =r-6[/tex]

Square both sides to get:

[tex]r^2-12r+36=r[/tex]

Subtract r to get:
[tex]r^2-13r+36=0[/tex]

Factor to get:
(r-9)(r-4)=0

The solutions to this equation are 9 and 4.
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