hannahmichelle
Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

2x^2-3x-9 please help

Sagot :

Im assuming you mean 2x^2-3x-9=0 ?
If so, you have to factorise the equation
(2x-3) (x+3) = 0

2x - 3 = 0
2x = 3
x = 1.5

x + 3 = 0
x = -3

x is either 1.5 or -3

apologiabiology
so  factor

if you have ax^2+bx+c then to factor find
x+y=b
xy=ac
so

a=2
b-03
c=-9
2 times -9=-18

factor -18
-1,18
-2, 9
-3, 6


now add and find the one that adds to -3


-1+18=17
-2+9=7
-3+ 6=3, could work, if signs are reversed

so the numbers are -6 and 3

split -3 up
2x^2-6x+3x-9
group
(2x^2-6x)+(3x-9)
undistribute
(2x)(x-3)+(3)(x-3)
reverse distributive property
ab+ac=a(b+c)
(2x+3)(x-3)


so we can't do anything else because it isn't an equation so it has non meaning

if it does equal zero then
xy=0 then x and/or y=0 so

(2x+3)(x-3)=0 so
2x+3=0 and x-3=0 so

2x+3=0
subtract 3 from both sides
2x=-3
divide by 2
x=-1.5

x-3=0
add 3 to both sides
x=3



x=-1.5 or 3

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.