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solve number 9 using quadratics

Solve Number 9 Using Quadratics class=

Sagot :

Panoyin
     5f² - 3f = 8
5f² - 3f - 8 = 0
f = -(-3) +/- √((-3)² - 4(5)(-8))
                     2(5)
f = 3 +/- √(9 + 160)
               10
f = 3 +/- √(169)
            10
f = 3 +/- 13
         10
f = 3 + 13      f = 3 - 13
        10                 10
f = 13            f = -10
     10                   10
f = 1.3           f = -1
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