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Find the distance between (2,3) and (5,8)

Sagot :

use pythagorean theorem
a^2+b^2=c^2

first find the difference of between the 2 points to find the legnth of the legs

distance between 2 and 5=3
distance between 3 and 8=5 so


3^2+5^2=c^2
9+25=c^2
34=c^2
√34=c

the ligit formula is
[tex]c= \sqrt{(x1-x2)^2+(y1-y2)^2} [/tex]

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