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In cocker spaniels the allele for a black coat color (B) is dominant over the allele for a brown coat color (b). If a brown cocker spaniel is crossed with a heterozygous black cocker spaniel, which of the following genotypic ratios can be expected?



0 BB: 2 Bb: 2 bb






1 BB: 2 Bb: 1 bb






2 BB: 0 Bb: 2 bb






2 BB: 1 Bb: 0 b



Sagot :

The first one .....  0 BB: 2 Bb: 2 bb  use punnett squares it helps, just search how to use them.
ajeigbeibraheem

The expected genotypic ratios are  0BB: 2Bb : 2bb. The 1st option is correct.

The Mendelian theory by George Mendel explains the monohybrid experiment crossing which can be achieved by the use of punnet square.

From the given information, in cocker spaniels

  • The allele for black coat color = B
  • The allele for brown coat color = b

If a brown cocker spaniel i.e bb (recessive trait) is crossed with a heterozygous black cocker spaniel i.e. Bb

Then, we can use the punnet square to determine their genotypes.

        b            b

B      Bb          Bb

b      bb           bb

Therefore, we can conclude that the genotypic ratios are 0BB: 2Bb : 2bb

Learn more about monohybrid crossing here:

https://brainly.com/question/24076691?referrer=searchResults

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