Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

The perimeter of a rectangular playing field is 244 feet. If its length is 2 feet longer than twice its width, what are the dimensions of the field?

Sagot :

jaguar155
Peri = 2A+2B 

244 = 2(2+2x) + 2(x)
The perimeter (P) of a polygon is all the values of all the sides added together. (Length+Length+Width+Width) If the length (L) of the rectangle is 2 feet longer than twice the width (W), then L=2W+2. So now the perimeter is 2W+2+2W+2+W+W = P. This simplifies to 6W+4=P. If we know the perimeter is 244, then 6W+4=244. Then subtract four and divide by 6. W=40. If L=2W+2, then L=2(40)+2, or L=82. SO.....
The width is 40 feet
The length is 82 feet

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.