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The perimeter of a rectangle is 116cm. The length is 10cm greater than twice the width. What is the length of the rectangle? Please show work!

Sagot :

SecretIndex
2L + 2W = 116
L = 2W + 10
2(2W+10) + 2W = 6W + 20 = 116
6W = 96
W = 16
L = 2W + 10
L = 2(16) + 10 = 32 + 10 = 42 cm
alex12678
Steps:
Write a Let Statement
Write out your equation
Solve for variable

Let
    n = the width
    2n + 10 = the length
    P = 116
    P = 2L + 2W

116 = 2(2n +10) +2n
116= 4n + 20 + 2n
116 = 6n + 20
96 = 6n
n = 16
The Length is 42 cm and the width is 16 cm.


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