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How Do You Do:
2(n-7)+3=9

And:
4h+7h-16=6

Sagot :

RedRicin
To solve equations with variables, we use inverse operations.
Inverse operations are operations that cancel each other out.
(plus and minus, multiply and divide)

Say we had [tex]x-3=6[/tex].
According to the addition property of equality, we could add 3 to each side of that equation and it would still be equal.
[tex]x-3+3=6+3[/tex]
This would cancel out the -3 and leave us with just [tex]x=9[/tex].

Question 1) Solve [tex]2(n-7)+3=9[/tex].

Let's just start cancelling things out. Doesn't matter what order.

[tex]2(n-7)+3=9 \\ 2(n-7)+3-3=9-3\\ 2(n-7)=6 \\\\\ \frac{2(n-7)}2=\frac{6}2\\n-7=3\\\\n-7+7=3+7\\\boxed{n=10}[/tex]

Question 2) Solve [tex]4h+7h-16=6[/tex].

You can add [tex]4h[/tex] and [tex]7h[/tex] together to get [tex]11h[/tex]. The h acts sort of like a unit in that case, like 4 feet + 7 feet = 11 feet.

[tex]11h-16=6\\11h-16+16=6+16\\11h=22\\\\\frac{11h}{11}=\frac{22}{11}\\\boxed{h=2}[/tex]
2 (n-7) +3=9 remove ( ) and distribute 2n-14+3=9 combine like terms 2n-11=9 add 11 to both sides 2n=20 n=10 4h+7h-16=6 combine like terms 11h-16=6 add 16 to both sides 11h=22 h= 2 hope this helps
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