Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
-- The difference of 2 logs is the log of the quotient of their arguments.
log(11) - log(6) = log(11/6)
-- 1/3 of the log of something is the log of its cube root.
1/3 log(8) = log(∛8) = log(2)
and
1/3 log(729) = log(∛729) = log(9)
-- If a bunch of logs all have the same base, then their sum
is the log of the product of the arguments. So ...
log(11) - log(6) + 1/3 log(8) + 1/3 log(729) =
log(11/6 times 2 times 9) =
log( 11*18 / 6 ) = log(33)
log(33) = about 1.519 (rounded)
============================================
The other way:
log(11) = 1.0414
-log(6) = -0.7782
log(8) = 0.9031
1/3(0.9031) = 0.3010
log(729) = 2.8627
1/3(2.8627) = 0.9542
-----------
Adum up: 1.5184
(Note: Everything is rounded.)
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.