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Answered

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You kick a ball with a speed of 14 m/s at an angle of 51 degrees. How far away does the ball land?
A. 21.3 m
B. 19.6 m
C. 1.8 m
D. 3.96 m

Sagot :

nehal
d may be the correct answer because speed is very low so ball should cover less distance  but angle is not very high so it can cover little much distance

Answer: The ball will land at 19.6 m

Explanation:

To calculate the horizontal range of the ball, we use the formula:

[tex]R=\frac{v^2\sin 2\theta}{g}[/tex]

where,

v = velocity of the ball = 14 m/s

[tex]\theta[/tex] = angle at which the ball is thrown = 51°

g = acceleration due to gravity = [tex]9.8m/s^2[/tex]

Putting values in above equation, we get:

[tex]R=\frac{(14)^2\times \sin (2\times 51)}{9.8}\\\\R=19.6m[/tex]

Hence, the ball will land at 19.6 m

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