Avis37
Answered

Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

A rocket carrying fireworks is launched from a hill 80 feet above a lake. The rocket will fall into the lake after exploding at its maximum height. The rocket's height above the surface of the lake is given by h=-16t^2+64t+80.
-what is the height of the rocket after 1.5 seconds?
-what is the maximum height reached by the rocket?
-how long will it take for the rocket to hit 128 ft?
-after how many seconds after its launched will the rocket hit the lake?


Sagot :

For first question, you can let t=1.5 and calculate h=140 ft. For second question, we can change the equation to the form of h=-16[(t-2)^2-9]. So you can see from the equation that the maximum height is created when t=2, equals to 144 ft. For question 3, let h=128. From equation, we can get t=3 or t=1. For last question, the rocket hit the lake means h=0, so t=5 or t=-1(not applicable). So the answer is t=5. You can also draw the graphic for the equation to help.