Answered

Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

How do I solve this.

Log 5x = log (2x+9)

Sagot :

konrad509
[tex]D:5x\ \textgreater \ 0 \wedge 2x+9\ \textgreater \ 0\\ D:x\ \textgreater \ 0 \wedge 2x\ \textgreater \ -9\\ D:x\ \textgreater \ 0 \wedge x\ \textgreater \ -\dfrac{9}{2}\\ D:x\ \textgreater \ 0\\\\ \log5x=\log(2x+9)\\ 5x=2x+9\\ 3x=9\\ x=3[/tex]
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.