Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
You can use logarithms:
Log9(27) which will give you the value of x
X= 1.5
Log9(27) which will give you the value of x
X= 1.5
[tex]9^x=27\\\\(3^2)^x=3^3\\\\3^{2\cdot x}=3^3\\\\3^{2x}=3^3\iff 2x=3\ \ \ /:2\Rightarrow x=1.5[/tex]
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.