Answered

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A sequence is defined recursively by f(1)=16 and f(n)=f(n-1)+2n. Find f(4)

1) 32

2) 30

3) 28

4) 34

Sagot :

kate200468
[tex]f(1)=16 \ \ \ and \ \ \ \ f(n)=f(n-1)+2n \\ \\f(2)=f(1)+2\cdot2=16+4=20\\ \\f(3)=f(2)+2\cdot3=20+6=26\\ \\f(4)=f(3)+2\cdot4 =26+8=34[/tex]

[tex]Ans.\ 4)[/tex]
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