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Sagot :
X/x+3=2/5. We are going to do 3-2/5. The first thing you do is make 3 a fraction:[tex] \frac{3}{1}[/tex]. Now the subtraction problem is [tex] \frac{3}{1}- \frac{2}{5} [/tex] Next we have to make common denominators for [tex] \frac{3}{1}[/tex] and [tex] \frac{2}{5}[/tex] [tex] \frac{3*5}{1*5}= \frac{15}{5} \ and \ \frac{2*1}{5*1}= \frac{2}{5}[/tex] Now we are going to subtract. [tex] \frac{15}{5}- \frac{2}{5}= \frac{13}{5}[/tex] So, X/x=[tex]\boxed{ \frac{13}{5}}[/tex] Hoped I helped. :)
[tex]\frac{x}{x + 3} = \frac{2}{5} \\2(x + 3) = 5x \\2(x) + 2(3) = 5x \\2x + 6 = 5x \\\frac{6}{3} = \frac{3x}{3} \\2 = x[/tex]
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