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consider this equation.
10x-6=3(5+x)
what is the value of x that makes this equation true?


Sagot :

3

10(3)-6 = 24
3(5+3) = 24
[tex]10x - 6 = 3(5 + x) \\10 - x = 3(5) + 3(x) \\10x - 6 = 15 + 3x \\7x - 6 = 15 \\\frac{7x}{7} = \frac{21}{7} \\x = 3[/tex]