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Use the quadratic formula to solve x^2 + 9x + 10 = 0. Estimate irrational solutions to the nearest tenth.

A {–3.6, 16.4}
B {–7.7, –1.3}
C {–25, 16}
D {–15.4, –2.6}


Sagot :

Basically, just plus your numbers into quadratic formula. A= 1, B= 9, C= 10.
The answer you will get is B.
[tex]x^{2} + 9x + 10 = 0 \\x = \frac{-(9) +/- \sqrt{(9)^{2} - 4(1)(10)}}{2(1)} \\x = \frac{-9 +/- \sqrt{81 - 40}}{2} \\x = \frac{-9 +/- \sqrt{41}}{2} \\x = \frac{-9 +/- 6.4}{2} \\x = \frac{-9 + 6.4}{2} \\x = \frac{-2.6}{2} \\x = -1.3 \\ \\x = \frac{-9 - 6.4}{2} \\x = \frac{-15.4}{2} \\x = -7.7[/tex]

It is equal to B.