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Sagot :
Answer: 21.3 km
Step-by-step explanation:
Given: On each of 3 days the distance traveled by Derrick to school = 6.45 km
The distance rode by Derrick to library = 150 meters
Since, 1 m=[tex]\frac{1}{1000}\ km[/tex]
Thus, the distance rode by Derrick to library = [tex]150\times\frac{1}{1000}\ km=0.15\ km[/tex]
The distance rode by Derrick to home = 500 meters.
Thus, the distance rode by Derrick to home = [tex]500\times\frac{1}{1000}\ km=0.5\ km[/tex]
Distance he rode in each day = [tex]6.45+0.15+0.5=7.1\ km[/tex]
Now, Distance he rode in 3 days = [tex]3\times7.1=21.3\ km[/tex]
Answer:
21.3 km.
Step-by-step explanation:
On each of 3 days, Derrick rode 6.45 km to school, 150 meters to the library, and then 500 meters back home.
We know that
1 km = 1000 m
6.45 km = 6450
Total distance covered by Derrick in one day = 6450+150+500 meters
= 7100 meters
=7.1 kilometers
The distance covered by Derrick on each day is 7.1 km. So, the distance covered by Derrick in 3 days is
[tex]Total =3\times 7.1[/tex]
[tex]Total =21.3[/tex]
Therefore, Derrick rides 21.3 km for the 3 days altogether.
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