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Sagot :
Next time, use the carrot for exponent like this:
x^2+7x+6=0
The first term is a , the second is b and the last is C
Quadratic is ax^2+bx+c=0
The formula is -(b) +- squareroot(b^2 -4(a)(c)) all over two a
So youve got:
-7 +- square root (49-4(1)(6)) divided by 2(1)
Simplify
-7 +- squareroot(49-24) / 2
-7 +- square root (25) / 2
25 is a perfect square of five, so tou have
(-7 + 5)/2 And (-7-5)/2
You answers should be : -1 & -6
x^2+7x+6=0
The first term is a , the second is b and the last is C
Quadratic is ax^2+bx+c=0
The formula is -(b) +- squareroot(b^2 -4(a)(c)) all over two a
So youve got:
-7 +- square root (49-4(1)(6)) divided by 2(1)
Simplify
-7 +- squareroot(49-24) / 2
-7 +- square root (25) / 2
25 is a perfect square of five, so tou have
(-7 + 5)/2 And (-7-5)/2
You answers should be : -1 & -6
x² + 7x + 6 = 0
x = -(7) +/- √((7)² - 4(1)(6))
2(1)
x = -7 +/- √(49 - 24)
2
x = -7 +/- √(25)
2
x = -7 +/- 5
2
x = -7 + 5 x = -7 - 5
2 2
x = 2 x = -12
2 2
x = 1 x = -6
The solution is equal to {1, -6}.
x = -(7) +/- √((7)² - 4(1)(6))
2(1)
x = -7 +/- √(49 - 24)
2
x = -7 +/- √(25)
2
x = -7 +/- 5
2
x = -7 + 5 x = -7 - 5
2 2
x = 2 x = -12
2 2
x = 1 x = -6
The solution is equal to {1, -6}.
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