Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
What's happening here is that you're changing the potential energy of this object by lifting it 500cm.
Therefore the energy required to lift it would be the additional potential energy it gains. Look at the equation for potential energy:
PE = m*g*h
and convert and plug in your values:
PE = (2.5kg) * (9.8 m/s²) * (0.5m)
PE = 12.25J
Therefore the energy required to lift it would be the additional potential energy it gains. Look at the equation for potential energy:
PE = m*g*h
and convert and plug in your values:
PE = (2.5kg) * (9.8 m/s²) * (0.5m)
PE = 12.25J
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.